Chapter 1Foundationsslides.en.pdf:64

Domino Induction

If dominos stand in line and the first falls, all fall

Theorem 2.11Domino Theorem
Concept

Theorem 2.11 (Domino Theorem). Let S1,S2,S3,S_1, S_2, S_3, \dots be a linear
sequence of dominos such that:
- S1S_1 falls, and
- for every kk, if SkS_k falls then Sk+1S_{k+1} also falls.

Then every SnS_n falls.

This is the practical meaning of the Peano induction axiom (P5). The dominos
are the natural numbers; each SkS_k falling means "the statement P(k)P(k) is true".
The first domino falling is the base case. The rule "if SkS_k falls then
Sk+1S_{k+1} falls" is the inductive step.

To prove nN.P(n)\forall n \in \mathbb{N}. P(n), you show:
1. P(0)P(0) (first domino falls)
2. n.P(n)P(s(n))\forall n. P(n) \Rightarrow P(s(n)) (if one falls, the next does)

Then by P5, every P(n)P(n) holds. ∎

Animation — domino
Transcript — click a line to jump7 cues
  1. 0.0sTheorem 2.11: Domino Induction
  2. 1.0sIf S1 falls and each falling domino knocks down the next, all Sn fall.
  3. 2.5sEight dominos S1 through S8 stand in a row.
  4. 3.7sNow we knock the first one over.
  5. 4.5sEach falling domino topples the next one in sequence.
  6. 6.5sCascade: the rule S_k falls implies S_{k+1} falls.
  7. 9.5sAll dominos fall. By induction, every Sn falls.
Worked example
Step 0 of 2
Practice — score 100% to advance
Multiple choice
Q1
What are the two parts of an induction proof?
Q2
In the domino metaphor, what does the first domino falling represent?
Q3
If you forget the base case, what can go wrong?
Q4
What is the form of the inductive hypothesis for P(n)P(n) over naturals?
Q5
True or false: induction lets us prove statements of the form nN.P(n)\forall n \in \mathbb{N}. P(n).
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